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| The energy budget of a female Yellowed headed Wagtail is ～7 9 kJ, apportioned protein is 0 kJ( 8%～ 0%) and the lipid is 8～ 0 78 kJ ( %～ %). |
中文意思：
产卵期 ,雌鸟用于性腺增长和卵形成的能量预算为 ～7 9kJ ,其中用于蛋白质和脂肪的能量分别为 0 kJ和 8～ 0 78kJ,占总能量预算的 8%～ 0 %和 %～ % . |
以下为相关句子列表(点击查看，可以看对应的解释）：
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The element A: one level is Ibotenic acid(IBA; μL,0 mmol/L) that was injected into the Meynert nucleus by using microdrive injector;
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三因素为:A因素:一水平为鹅膏蕈氨酸(IBA)一次性微量(μL,0mmol/L)注入大鼠Meynert基底核; |
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The elemental analysisreveals the molecular formula of β-(, ) glucan is(CH0O)n.
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元素分析认为 β - (, )葡聚糖的分子通式为 (CH0 O) n。 |
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The empiric use of antinations composed 00% and 98. % respectively.
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经验性用药分别占00%和98. %。 |
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The employee is trained
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欣赏“领带”式员工培训 |
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The emulation result shows:this controller has better control result and stupid and excellent.
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仿真结果表明该控制器有较好的控制效果和鲁棒性。 |
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The energy budget of a female Yellowed headed Wagtail is ～7 9 kJ, apportioned protein is 0 kJ( 8%～ 0%) and the lipid is 8～ 0 78 kJ ( %～ %).
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产卵期 ,雌鸟用于性腺增长和卵形成的能量预算为 ～7 9kJ ,其中用于蛋白质和脂肪的能量分别为 0 kJ和 8～ 0 78kJ,占总能量预算的 8%～ 0 %和 %～ % . |
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The enforced by France Peugeot Citron P.S.
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介绍了法国标致 /雪铁龙P . S . |
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The engineering bacteria LEY were constructed with the method of genes to transform the spheroplast, use Acinetobacter ealcoaceticus T and Pseudomonas putida -8, Arthobacter sp. # as receptor and donor.
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工程菌 LEY是以乙酸钙不动杆菌 T 株 ( Acinetobacter calcoaceticns T )为受体 ,恶臭假单胞菌 - 8株 ( Pseudomonasputida- 8 ) ,节杆菌 #株 ( Arthrobacter sp#)为供体 ,采用多基因转化受体原生质球构建而成。 |
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The engineering geologic conditions in the selected area of constructing LPG underground storage caverns played a decisive role.
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在LPG地下洞库的建设中，选区的工程地质条件起决定性作用。 |
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The enolate Claisen rearrangement can reduce a chiral carbon, aid-ehyde group that was reduced by reduction was also a potential chiral carbon. So, this reaction can open a new route for preparing chiral compound.
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由于酯的烯醇化Claisen重排反应可以产生一个手性碳，而还原产生的醛基也是一个潜在的手性碳，所以此反应可以为进一步合成手性化合物开辟一条新的途径。 |
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The enrichment ability of scallop according to the sequence Cd>Zn>As>Hg>Cu>Pb≈Cr。
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同时分析结果表明,栉孔扇贝对不同的重金属富集特性不同,依次是Cd>Zn>As>Hg>Cu>Pb≈Cr。 |
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